📘 CBSE CLASS 12 — MASTER MATHEMATICS SYSTEM
PART 1: CHAPTERS 1–5
Chief Examiner Edition | 2014–2025 Trend Analysis
CHAPTER 1: RELATIONS AND FUNCTIONS
SECTION A — FORMULA SHEET
Types of Relations
- Reflexive: (a, a) ∈ R for all a ∈ A
- Symmetric: (a, b) ∈ R ⟹ (b, a) ∈ R
- Transitive: (a, b) ∈ R and (b, c) ∈ R ⟹ (a, c) ∈ R
- Equivalence Relation: Reflexive + Symmetric + Transitive
Types of Functions
- Injective (One-One): f(a) = f(b) ⟹ a = b
- Surjective (Onto): Range = Co-domain
- Bijective: One-One + Onto
- Inverse exists only if f is Bijective
Composition of Functions
- (g∘f)(x) = g(f(x))
- (f∘g) ≠ (g∘f) in general
- If f: A→B and g: B→C, then g∘f: A→C
Binary Operations
- Commutative: a * b = b * a
- Associative: (a * b) * c = a * (b * c)
- Identity element e: a * e = e * a = a
- Inverse of a: a * a⁻¹ = e
- Closure: a, b ∈ S ⟹ a * b ∈ S
SECTION B — METHODS
Checking Equivalence Relation:
- State Reflexive: Show (a,a) ∈ R — write formal proof
- State Symmetric: Assume (a,b) ∈ R, prove (b,a) ∈ R
- State Transitive: Assume (a,b) and (b,c) ∈ R, prove (a,c) ∈ R
- Conclude: R is an equivalence relation
Checking One-One:
- Method 1 (Algebraic): Let f(x₁) = f(x₂), show x₁ = x₂
- Method 2 (Graph): Horizontal line test
- Method 3 (Derivative): If f'(x) > 0 or f'(x) < 0 always, then one-one
Checking Onto:
- Let y = f(x), solve for x in terms of y
- Show x is real and in domain for all y in co-domain
Finding Inverse:
- Let y = f(x)
- Express x in terms of y: x = g(y)
- Replace y with x: f⁻¹(x) = g(x)
SECTION C — SHORTCUTS
- Equivalence class of element a = {b ∈ A : (a,b) ∈ R}
- Number of relations from A to B = 2^(n(A)×n(B))
- Number of functions from A to B = (n(B))^(n(A))
- Number of bijections from A to A = n(A)!
- If f is one-one from finite set A to A, it is automatically onto
- For proving NOT one-one: Give a counterexample where f(a) = f(b), a ≠ b
- For proving NOT onto: Find one y in co-domain with no preimage
SECTION D — COMMON QUESTION TYPES
1 Mark:
- Identify type of relation from definition
- State whether function is bijective (yes/no with reason)
2 Mark:
- Prove a given relation is equivalence / not equivalence
- Find inverse of a simple function
3–4 Mark (Most repeated):
- Prove f is bijective, find f⁻¹
- Prove equivalence relation on ℤ or ℝ
- Find equivalence class of an element
Long Answer:
- Prove f∘g is bijective if f and g are bijective
- Determine identity and inverse under binary operation
SECTION E — COMMON MISTAKES
- ❌ Not checking all THREE properties for equivalence
- ❌ Proving (a,b)∈R but forgetting (b,a)∈R for symmetry
- ❌ Using wrong domain while finding inverse
- ❌ Confusing "not onto" with "not one-one"
- ❌ Forgetting to state "Hence f is bijective" at end
SECTION F — SCORING STRATEGY
- Start with: Definitions (easy 1 mark)
- Safe marks: Reflexive + Symmetric steps always carry partial credit
- Don't skip: Conclusion line ("Hence R is equivalence relation")
- Quick win: Check one-one with derivative for continuous functions
CHAPTER 2: INVERSE TRIGONOMETRIC FUNCTIONS
SECTION A — FORMULA SHEET
Principal Ranges
| Function | Domain | Range |
|---|---|---|
| sin⁻¹x | [-1,1] | [-π/2, π/2] |
| cos⁻¹x | [-1,1] | [0, π] |
| tan⁻¹x | ℝ | (-π/2, π/2) |
| cot⁻¹x | ℝ | (0, π) |
| sec⁻¹x | x | |
| cosec⁻¹x | x |
Key Identities
- sin⁻¹x + cos⁻¹x = π/2
- tan⁻¹x + cot⁻¹x = π/2
- sec⁻¹x + cosec⁻¹x = π/2
Negative Argument Rules
- sin⁻¹(−x) = −sin⁻¹x
- cos⁻¹(−x) = π − cos⁻¹x
- tan⁻¹(−x) = −tan⁻¹x
Double & Sum Formulas
- 2tan⁻¹x = sin⁻¹(2x/1+x²) = cos⁻¹(1−x²/1+x²) = tan⁻¹(2x/1−x²)
- tan⁻¹x + tan⁻¹y = tan⁻¹((x+y)/(1−xy)), if xy < 1
- tan⁻¹x − tan⁻¹y = tan⁻¹((x−y)/(1+xy))
Conversion Identities
- sin⁻¹x = cos⁻¹(√1−x²) = tan⁻¹(x/√1−x²)
- cos⁻¹x = sin⁻¹(√1−x²) = tan⁻¹(√1−x²/x)
SECTION B — METHODS
Simplifying ITF Expressions:
- Identify which formula applies (addition, double angle, etc.)
- Substitute and simplify step by step
- Apply range check if needed
- Write final value in terms of π
Proving ITF Equations:
- Take LHS, apply relevant identity
- Simplify to RHS = proved
- State "LHS = RHS, Hence Proved"
Solving ITF Equations:
- Isolate inverse trig function
- Apply tan/sin/cos to both sides
- Solve algebraic equation
- Verify solution lies in principal range
SECTION C — SHORTCUTS
- Remember: sin⁻¹ + cos⁻¹ = π/2 (use whenever 2 ITF terms appear)
- Quick tan⁻¹ addition: Check if xy < 1, = 1, or > 1 first!
- Convert to tan⁻¹: Most problems simplify using tan⁻¹ form
- 2tan⁻¹x = sin⁻¹(2x/1+x²) — memorize this, used in 4-mark questions
- For cos⁻¹(−x): Always write π − cos⁻¹(x), not − cos⁻¹(x)
SECTION D — COMMON QUESTION TYPES
1 Mark:
- Find value: sin⁻¹(sin 3π/5), cos(sin⁻¹ 1/2)
- Simplify: tan⁻¹(1) + cos⁻¹(−1/2)
2 Mark:
- Prove: 2tan⁻¹(1/2) + tan⁻¹(1/7) = π/4
- Simplify an ITF expression
3–4 Mark:
- Solve: tan⁻¹(2x) + tan⁻¹(3x) = π/4
- Prove: tan⁻¹(x) + tan⁻¹(2x/(1−x²)) = tan⁻¹(3x−x³/1−3x²)
SECTION E — COMMON MISTAKES
- ❌ cos⁻¹(−x) = −cos⁻¹x (WRONG — it's π − cos⁻¹x)
- ❌ Not checking xy vs 1 before applying tan addition formula
- ❌ Forgetting principal range while verifying solutions
- ❌ Writing sin⁻¹(sin x) = x without checking x ∈ [−π/2, π/2]
SECTION F — SCORING STRATEGY
- Memorize all identities — direct formula substitution = full marks
- Write each identity used explicitly for step marks
- Range errors = −1 mark; always double-check
CHAPTER 3: MATRICES
SECTION A — FORMULA SHEET
Matrix Operations
- Addition: (A+B)ᵢⱼ = Aᵢⱼ + Bᵢⱼ (same order only)
- Scalar Multiplication: (kA)ᵢⱼ = k·Aᵢⱼ
- Multiplication: (AB)ᵢⱼ = Σ Aᵢₖ · Bₖⱼ; requires A(m×n)·B(n×p) = C(m×p)
- Transpose: (Aᵀ)ᵢⱼ = Aⱼᵢ
Transpose Properties
- (A+B)ᵀ = Aᵀ + Bᵀ
- (AB)ᵀ = BᵀAᵀ
- (Aᵀ)ᵀ = A
- (kA)ᵀ = kAᵀ
Symmetric & Skew-Symmetric
- Symmetric: Aᵀ = A → aᵢⱼ = aⱼᵢ
- Skew-Symmetric: Aᵀ = −A → aᵢⱼ = −aⱼᵢ → diagonal = 0
- Any matrix: A = ½(A+Aᵀ) + ½(A−Aᵀ) [Sym + Skew]
Inverse (2×2)
- If A = [[a,b],[c,d]], then A⁻¹ = 1/(ad−bc) × [[d,−b],[−c,a]]
- A⁻¹ exists iff |A| ≠ 0
Key Results
- AI = IA = A
- A·A⁻¹ = I
- (AB)⁻¹ = B⁻¹A⁻¹
- (Aⁿ)⁻¹ = (A⁻¹)ⁿ
SECTION B — METHODS
Finding Element from Matrix Equation:
- Find Aᵀ, −Aᵀ, etc.
- Perform matrix operations step by step
- Compare corresponding elements
- Extract unknown values
Expressing as Sum of Sym + Skew:
- Find Aᵀ
- Symmetric part P = ½(A + Aᵀ)
- Skew-Symmetric part Q = ½(A − Aᵀ)
- Verify A = P + Q
Matrix Proof (A² − 5A + 6I = 0):
- Calculate A²
- Calculate 5A
- Subtract and add 6I
- Show = 0 (zero matrix)
SECTION C — SHORTCUTS
- Order of product: Always check compatibility before multiplying
- Diagonal of skew-symmetric = always 0 (instant check)
- If A = Aᵀ: symmetric (all elements mirror about diagonal)
- For proofs: Work from LHS, expand using given conditions
- 2×2 inverse: Cross multiply, negate off-diagonal, divide by |A|
SECTION D — COMMON QUESTION TYPES
1 Mark:
- Order of matrix, number of elements
- Identify symmetric/skew-symmetric
2 Mark:
- Find x, y from matrix equation
- Find transpose of a given matrix
3–4 Mark (Most repeated 2014–2025):
- Express matrix as sum of symmetric and skew-symmetric
- Prove matrix equation (A² − kA + I = 0 type)
- Find A⁻¹ by elementary row operations
Long Answer:
- Use matrices to solve system of equations (via inverse)
SECTION E — COMMON MISTAKES
- ❌ Multiplying matrices in wrong order (AB ≠ BA)
- ❌ Forgetting diagonal of skew-symmetric must be 0
- ❌ Wrong formula for 2×2 inverse (mixing up signs)
- ❌ Not verifying P + Q = A after decomposition
SECTION F — SCORING STRATEGY
- Matrix equations: Write every step row by row
- Show full calculation for A² even if tedious
- Never skip: State "A = P + Q" explicitly at the end
CHAPTER 4: DETERMINANTS
SECTION A — FORMULA SHEET
Expansion (2×2 and 3×3)
- |A| for 2×2 = ad − bc
- |A| for 3×3 = a₁(b₂c₃−b₃c₂) − b₁(a₂c₃−a₃c₂) + c₁(a₂b₃−a₃b₂)
Properties of Determinants
- If two rows/columns are identical → |A| = 0
- Interchange of two rows → |A| changes sign
- Row/column multiplication by k → |A| multiplied by k
- |kA| = kⁿ|A| for n×n matrix
- |Aᵀ| = |A|
- |AB| = |A|·|B|
- Adding scalar multiple of one row to another → |A| unchanged
Adjoint and Inverse
- adj(A) = transpose of cofactor matrix
- A⁻¹ = adj(A)/|A|
- A·adj(A) = |A|·I
- |adj(A)| = |A|^(n−1) for n×n matrix
Area of Triangle
- Area = ½|x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|
- In determinant form: ½|det matrix|
Collinearity
- Points are collinear if determinant = 0
Cramer's Rule / Matrix Method
- AX = B → X = A⁻¹B (only if |A| ≠ 0)
- If |A| = 0: inconsistent or infinitely many solutions
SECTION B — METHODS
Solving Determinant Proofs Using Row/Column Operations:
- Take out common factors from rows/columns first
- Apply R₁ → R₁ − R₂, R₂ → R₂ − R₃ (or C operations)
- Expand after simplification
- Factor and simplify to match RHS
Solving System via Matrix Inverse Method:
- Write in form AX = B
- Find |A|; if ≠ 0 proceed
- Find adj(A)
- Find A⁻¹ = adj(A)/|A|
- X = A⁻¹B → solve for x, y, z
SECTION C — SHORTCUTS
- Take common from rows first before expanding — saves time
- C₁ + C₂ + C₃: When all row sums are equal, factor out (a+b+c)
- R₁ − R₂, R₂ − R₃: Creates zeros, makes expansion easy
- Check |A| = 0 first: No need to find inverse if system is inconsistent
- For area: Just memorize the ½|det| formula — no coordinate geometry needed
SECTION D — COMMON QUESTION TYPES
1 Mark:
- Find value of a determinant
- State condition for consistency of equations
2 Mark:
- Find area of triangle using determinant
- Check if points are collinear
3–4 Mark (Most repeated 2014–2025):
- Prove determinant identity using properties (R/C operations)
- Solve system of 3 equations using matrix method
Long Answer:
- Find A⁻¹ using adj, solve AX = B
- 5-step determinant identity proof
SECTION E — COMMON MISTAKES
- ❌ Expanding 3×3 without taking common factor out first
- ❌ Wrong sign pattern (+−+ for cofactors)
- ❌ Using Cramer's rule when |A| = 0
- ❌ Forgetting ½ in area formula
- ❌ Not checking consistency when asked "does solution exist?"
SECTION F — SCORING STRATEGY
- Determinant proofs: Start with LHS = (write det), then use ops
- 3-equation system: 5 steps = 5 marks, write ALL steps
- Quick attempt: Area of triangle = guaranteed marks if formula known
CHAPTER 5: CONTINUITY AND DIFFERENTIABILITY
SECTION A — FORMULA SHEET
Continuity Conditions
- f is continuous at x = a if: lim(x→a⁻) f(x) = lim(x→a⁺) f(x) = f(a)
- If any one ≠, then discontinuous
Standard Derivatives
| f(x) | f'(x) |
|---|---|
| xⁿ | nxⁿ⁻¹ |
| eˣ | eˣ |
| aˣ | aˣ ln a |
| ln x | 1/x |
| sin x | cos x |
| cos x | −sin x |
| tan x | sec²x |
| cot x | −cosec²x |
| sec x | sec x tan x |
| cosec x | −cosec x cot x |
| sin⁻¹x | 1/√(1−x²) |
| cos⁻¹x | −1/√(1−x²) |
| tan⁻¹x | 1/(1+x²) |
| cot⁻¹x | −1/(1+x²) |
Chain, Product, Quotient Rules
- Chain: d/dx[f(g(x))] = f'(g(x))·g'(x)
- Product: d/dx[uv] = u'v + uv'
- Quotient: d/dx[u/v] = (u'v − uv')/v²
Implicit Differentiation
- Differentiate both sides w.r.t. x
- Collect dy/dx terms, solve
Logarithmic Differentiation
- Take ln of both sides, differentiate, multiply by y
Parametric Differentiation
- dy/dx = (dy/dt)/(dx/dt)
Second Order Derivative
- d²y/dx² = d/dx(dy/dx)
Rolle's Theorem
- If f: [a,b] → ℝ, continuous on [a,b], differentiable on (a,b), f(a)=f(b)
- Then ∃ c ∈ (a,b) such that f'(c) = 0
Mean Value Theorem (Lagrange's)
- If f: [a,b] → ℝ, continuous on [a,b], differentiable on (a,b)
- Then ∃ c ∈ (a,b) such that f'(c) = [f(b)−f(a)]/(b−a)
SECTION B — METHODS
Continuity at a Point (Piecewise):
- Find LHL = lim(x→a⁻) f(x) using left piece
- Find RHL = lim(x→a⁺) f(x) using right piece
- Find f(a) from definition
- If LHL = RHL = f(a) → continuous; else discontinuous
Logarithmic Differentiation:
- Let y = [complex expression]
- Take ln y = ln(expression) → simplify using log laws
- Differentiate both sides w.r.t. x
- Multiply both sides by y
- Substitute y back
Finding dy/dx for Implicit Function:
- Differentiate term by term
- Group all dy/dx terms on left
- Factor out dy/dx
- Divide to isolate dy/dx
SECTION C — SHORTCUTS
- Quick continuity check: LHL = RHL = f(a) — this is the only test
- Piecewise at integer: Substitute x = k⁻ and x = k⁺
- Derivative of (f(x))^g(x): Always use log differentiation
- If exponent has x: eˣ rule or log diff — never power rule
- For parametric: dy/dx = (dy/dt)÷(dx/dt), simplify t terms
SECTION D — COMMON QUESTION TYPES
1 Mark:
- Find derivative of simple composite function
- Is f(x) differentiable at x = 0?
2 Mark:
- Find dy/dx for given implicit/parametric function
- Verify Rolle's theorem on [a,b]
3–4 Mark (Highly repeated):
- Find dy/dx using log diff (e.g., y = (sin x)^x + x^sin x)
- If y = (tan⁻¹x)², prove (1+x²)²y₂ + 2x(1+x²)y₁ = 2
- Find d²y/dx² from parametric equations
Long Answer:
- Prove differentiability — show LHD ≠ RHD or LHD = RHD
SECTION E — COMMON MISTAKES
- ❌ Using power rule for eˣ type functions
- ❌ Forgetting chain rule for composite functions
- ❌ Not checking f(a) separately for piecewise continuity
- ❌ Not simplifying ln before differentiating (log diff)
- ❌ Missing the multiplication by y at the end of log diff
SECTION F — SCORING STRATEGY
- Continuity: Show 3 values clearly — LHL, RHL, f(a); conclusion line essential
- Log differentiation: Write each log law step explicitly
- Derivative questions: Show chain rule steps to earn step marks
- MVT/Rolle's: State theorem, verify conditions, then find c
End of Part 1 — Chapters 1 to 5 Continue in: MATHS_MASTER_PART2_CH6-9.md
📘 CBSE CLASS 12 — MASTER MATHEMATICS SYSTEM
PART 2: CHAPTERS 6–9
Chief Examiner Edition | 2014–2025 Trend Analysis
CHAPTER 6: APPLICATIONS OF DERIVATIVES (AOD)
SECTION A — FORMULA SHEET
Rate of Change
- Rate of change of y w.r.t. x = dy/dx
- Rate of change w.r.t. time: dy/dt = (dy/dx)·(dx/dt)
Increasing / Decreasing Functions
- f is increasing on (a,b) if f'(x) > 0 for all x ∈ (a,b)
- f is decreasing on (a,b) if f'(x) < 0 for all x ∈ (a,b)
- f'(x) = 0 at critical points
Local Maxima / Minima (First Derivative Test)
- At c: f'(c) = 0
- Changes from + to − → Local Maximum
- Changes from − to + → Local Minimum
- No change → neither
Second Derivative Test
- f'(c) = 0 and f''(c) < 0 → Local Maximum at c
- f'(c) = 0 and f''(c) > 0 → Local Minimum at c
- f''(c) = 0 → inconclusive, use first derivative test
Absolute Maxima/Minima (on closed interval [a,b])
- Find all critical points c where f'(c) = 0
- Evaluate f(a), f(b), f(c₁), f(c₂),...
- Largest value = Absolute Max; Smallest = Absolute Min
Tangent and Normal
- Slope of tangent at (x₁,y₁) = dy/dx at (x₁,y₁) = m
- Equation of tangent: y − y₁ = m(x − x₁)
- Slope of normal = −1/m
- Equation of normal: y − y₁ = −1/m (x − x₁)
Approximation
- Δy ≈ dy = f'(x)·Δx
- f(x + Δx) ≈ f(x) + f'(x)·Δx
SECTION B — METHODS
Finding Intervals of Increasing/Decreasing:
- Find f'(x)
- Set f'(x) = 0, find critical points
- Sign test in each interval
- State: f is increasing on (...) and decreasing on (...)
Optimization (Max/Min Word Problem):
- Define variables, write objective function
- Use given constraint to reduce to one variable
- Differentiate, set = 0
- Confirm with 2nd derivative or sign change
- Calculate dimensions/value, state answer with units
Tangent/Normal at a Point:
- Differentiate y = f(x) to get dy/dx
- Substitute x₁ to get slope m
- Write tangent: y − y₁ = m(x − x₁)
- Write normal: y − y₁ = −1/m (x − x₁)
SECTION C — SHORTCUTS
- Critical points: f'(x) = 0 or f'(x) undefined
- For closed interval max/min: Evaluate endpoints + critical points — compare all values
- Normal slope = negative reciprocal of tangent slope
- Approximation: Δy = dy/dx × Δx (quick substitution)
- Word problems: Always state what x and y represent before solving
SECTION D — COMMON QUESTION TYPES
1 Mark:
- Find rate of change (e.g., area of circle w.r.t. radius)
- Approximate value using derivatives
2 Mark:
- Find equation of tangent at given point
- Find intervals where f is increasing/decreasing
3–4 Mark (Most repeated 2014–2025):
- Optimization: rectangle in circle, box with no lid, etc.
- Find absolute max/min on closed interval
- Prove a function is strictly increasing/decreasing
Long Answer:
- Full optimization problem: cylinder inscribed in sphere, fencing problems
SECTION E — COMMON MISTAKES
- ❌ Not verifying critical points with 2nd test or sign change
- ❌ Forgetting to check endpoints for absolute max/min
- ❌ Sign error in slope of normal (should be −1/m)
- ❌ Not stating units in final answer (word problems)
- ❌ Not writing "Hence proved" for strictly increasing proofs
SECTION F — SCORING STRATEGY
- Max/min word problems: Write full setup — examiners give marks for each step
- Tangent/normal: 2 marks for slope, 1 mark for final equation
- Increasing/decreasing: Write interval explicitly, not just sign
CHAPTER 7: INTEGRALS
SECTION A — FORMULA SHEET
Standard Integrals
| Function | Integral |
|---|---|
| xⁿ | xⁿ⁺¹/(n+1) + C, n≠−1 |
| 1/x | ln |
| eˣ | eˣ + C |
| aˣ | aˣ/ln a + C |
| sin x | −cos x + C |
| cos x | sin x + C |
| tan x | ln |
| cot x | ln |
| sec x | ln |
| cosec x | ln |
| sec²x | tan x + C |
| cosec²x | −cot x + C |
| sec x tan x | sec x + C |
| cosec x cot x | −cosec x + C |
| 1/√(1−x²) | sin⁻¹x + C |
| −1/√(1−x²) | cos⁻¹x + C |
| 1/(1+x²) | tan⁻¹x + C |
Special Integral Forms
- ∫ 1/(x²−a²) dx = 1/2a · ln|(x−a)/(x+a)| + C
- ∫ 1/(a²−x²) dx = 1/2a · ln|(a+x)/(a−x)| + C
- ∫ 1/(x²+a²) dx = 1/a · tan⁻¹(x/a) + C
- ∫ 1/√(x²−a²) dx = ln|x + √(x²−a²)| + C
- ∫ 1/√(x²+a²) dx = ln|x + √(x²+a²)| + C
- ∫ 1/√(a²−x²) dx = sin⁻¹(x/a) + C
- ∫ √(a²−x²) dx = x/2·√(a²−x²) + a²/2·sin⁻¹(x/a) + C
Integration by Parts (IBP)
- ∫ u·v dx = u·∫v dx − ∫(u'·∫v dx) dx
- ILATE Rule: Inverse trig > Logarithm > Algebraic > Trig > Exponential
Definite Integral Properties
- ∫ₐᵇ f(x)dx = −∫ᵦₐ f(x)dx
- ∫ₐᵇ f(x)dx = ∫ₐᵇ f(a+b−x)dx
- ∫₀ᵃ f(x)dx = ∫₀ᵃ f(a−x)dx
- ∫₀²ᵃ f(x)dx = 2∫₀ᵃ f(x)dx if f(2a−x) = f(x); = 0 if f(2a−x) = −f(x)
- ∫₋ₐᵃ f(x)dx = 2∫₀ᵃ f(x)dx if f is even; = 0 if f is odd
SECTION B — METHODS
Integration by Substitution:
- Identify inner function u = g(x)
- Find du = g'(x)dx
- Substitute, integrate w.r.t. u
- Back-substitute to get answer in x
Partial Fractions:
- Linear factors: A/(x−a) + B/(x−b)
- Repeated linear: A/(x−a) + B/(x−a)²
- Irreducible quadratic: (Ax+B)/(x²+bx+c)
- Multiply through, compare coefficients
Integration by Parts (ILATE):
- Identify u (ILATE priority) and v
- Apply formula: u·∫v dx − ∫[u' · ∫v dx] dx
- If integral repeats → move to LHS, solve
Definite Integrals Using Properties:
- Identify which property applies
- Write I = ∫f(x)dx, then I = ∫f(a+b−x)dx
- Add both: 2I = ∫[constant]dx
- Solve for I
SECTION C — SHORTCUTS
- Quick recognition: 1/(x²+a²) → tan⁻¹, 1/√(a²−x²) → sin⁻¹
- Completing the square: For ax²+bx+c type denominators
- ∫eˣ[f(x)+f'(x)]dx = eˣf(x) + C — memorize this!
- For trig integrals: Use sin²x = (1−cos2x)/2, cos²x = (1+cos2x)/2
- For ∫₀^(π/2) sinⁿx: Use reduction formula (Wallis)
- Odd/Even shortcut: Check f(−x) first before computing definite integral
SECTION D — COMMON QUESTION TYPES
1 Mark:
- Evaluate ∫(simple function)dx
- Use property to find ∫₋ₐᵃ (odd function)
2 Mark:
- Integrate by substitution: ∫sin x·cos x dx, ∫eˣ sin x dx
- Evaluate simple definite integral
3–4 Mark (Most repeated 2014–2025):
- Integrate using partial fractions: ∫1/(x²−1)dx style
- Integration by parts: ∫x·eˣ dx, ∫x·sin x dx, ∫ln x dx
- Evaluate definite integral using properties
Long Answer:
- ∫√(a²−x²)dx type (with formula derivation)
- Definite integral 0 to π using property and solving 2I
SECTION E — COMMON MISTAKES
- ❌ Forgetting +C in indefinite integrals
- ❌ Wrong ILATE order (e.g., choosing eˣ over x as u)
- ❌ Not applying chain rule during substitution
- ❌ Not changing limits in definite integral during substitution
- ❌ Using wrong partial fraction form for repeated roots
SECTION F — SCORING STRATEGY
- IBP: Show u and v clearly as first line
- Partial fractions: Find A, B, C — each correct = 1 mark
- Definite integrals (property type): Show I = ... and I = ... before adding
- Always state: "By ILATE rule, let u = ... and v = ..."
CHAPTER 8: APPLICATIONS OF INTEGRALS
SECTION A — FORMULA SHEET
Area Under a Curve
- Area = ∫ₐᵇ |f(x)| dx (w.r.t. x-axis)
- Area between two curves: ∫ₐᵇ [f(x) − g(x)] dx where f(x) ≥ g(x)
Standard Areas
- Area under y = x: ½x² |ₐᵇ
- Area under y = x²: x³/3 |ₐᵇ
- Circle x² + y² = r²: Area = πr²
- Ellipse x²/a² + y²/b² = 1: Area = πab
- Area of parabola y² = 4ax from 0 to x: (2/3)·base·height
Area Between Line and Parabola (Common Board Type)
- Find intersection points
- ∫ₐᵇ [(upper curve) − (lower curve)] dx
SECTION B — METHODS
Finding Area Using Definite Integral:
- Sketch the region (rough sketch helps)
- Find limits of integration (intersection points)
- Identify upper and lower functions
- Integrate: ∫[upper − lower]dx
- Evaluate with limits
Area Between Two Curves:
- Solve to find intersection points → limits a, b
- Determine which curve is on top in [a,b]
- A = ∫ₐᵇ [f(x) − g(x)] dx
- Simplify and evaluate
SECTION C — SHORTCUTS
- Parabola + line: Always find intersection by substitution
- Circle quarter: Area = πr²/4 → use for symmetry
- Symmetric regions: Double the integral over half region
- Rough sketch: Saves time — identify positive/negative regions immediately
SECTION D — COMMON QUESTION TYPES
2 Mark:
- Find area bounded by simple curve and x-axis
3–5 Mark (Most repeated 2014–2025):
- Area enclosed by parabola and line
- Area of circle/ellipse using integration
- Area between two parabolas or line-parabola
Long Answer (Case Study / Long Q):
- Area of triangle using integration
- Region described by inequalities — find area
SECTION E — COMMON MISTAKES
- ❌ Forgetting to find intersection points (wrong limits)
- ❌ Integrating lower − upper (wrong sign → negative area)
- ❌ Not taking absolute value when curve goes below x-axis
- ❌ Not simplifying the area expression before writing final answer
SECTION F — SCORING STRATEGY
- Draw the figure: Examiners award mark for correct diagram
- Show limits: Write limits of integration clearly
- Evaluate step by step: Not on calculator — show all arithmetic
CHAPTER 9: DIFFERENTIAL EQUATIONS
SECTION A — FORMULA SHEET
Order and Degree
- Order: Order of the highest derivative
- Degree: Power of highest order derivative (after removing radicals)
- Degree undefined if trig/log of derivatives present
Types of Differential Equations
- Variable Separable: f(x)dx = g(y)dy → integrate both sides
- Homogeneous: F(x,y) = xⁿF(y/x) → put y = vx
- Linear DE: dy/dx + Py = Q where P, Q are functions of x
- Exact: (if M dx + N dy = 0 and ∂M/∂y = ∂N/∂x)
Linear DE Solution Method
- Integrating Factor (IF) = e^∫P dx
- Solution: y·IF = ∫(Q·IF) dx + C
Variable Separable
- Separate: f(y) dy = g(x) dx
- Integrate: ∫f(y) dy = ∫g(x) dx + C
Homogeneous DE
- Put y = vx → dy/dx = v + x·dv/dx
- Separate variables, integrate
- Back-substitute v = y/x
General and Particular Solution
- General: contains arbitrary constant C
- Particular: C found from initial condition
SECTION B — METHODS
Variable Separable:
- Rearrange to f(y)dy = g(x)dx
- Integrate both sides
- Write general solution with +C
- Apply initial condition if given to find C
Homogeneous DE:
- Verify homogeneous: check F(tx, ty) = tⁿF(x,y)
- Substitute y = vx, dy/dx = v + x·dv/dx
- Separate variables (v and x)
- Integrate both sides
- Substitute back v = y/x
Linear DE:
- Write in standard form: dy/dx + Py = Q
- Find IF = e^∫P dx
- Multiply through by IF
- LHS = d/dx(y·IF), integrate RHS
- Write: y·IF = ∫Q·IF dx + C
SECTION C — SHORTCUTS
- Identify type first: Before solving, classify the DE
- Variable separable: Products of f(x)·g(y) type
- Homogeneous check: Replace x→tx, y→ty; if tⁿ factors out → homogeneous
- Linear DE: P and Q in terms of x only (for dy/dx form)
- e^∫P dx: Simplify thoroughly — many times it's just eˣ or xⁿ
SECTION D — COMMON QUESTION TYPES
1 Mark:
- Find order and degree
- State type of DE
2 Mark:
- Form a DE from given family of curves
- Solve simple variable separable
3–4 Mark (Most repeated 2014–2025):
- Solve homogeneous DE
- Solve linear first-order DE
- Find particular solution given initial condition
Long Answer:
- Full word problem using DE (population growth, Newton's law of cooling, etc.)
SECTION E — COMMON MISTAKES
- ❌ Confusing order and degree
- ❌ Not identifying DE type before solving
- ❌ Forgetting +C in general solution
- ❌ Not substituting back v = y/x in homogeneous
- ❌ Wrong IF calculation — integrate P, then raise to e
SECTION F — SCORING STRATEGY
- Identify and state type of DE at the start (1 free mark)
- IF method: Write IF formula, compute, then proceed
- Particular solution: Substitute initial condition clearly
- Final answer: State general/particular solution explicitly
End of Part 2 — Chapters 6 to 9 Continue in: MATHS_MASTER_PART3_CH10-13.md
📘 CBSE CLASS 12 — MASTER MATHEMATICS SYSTEM
PART 3: CHAPTERS 10–13
Chief Examiner Edition | 2014–2025 Trend Analysis
CHAPTER 10: VECTORS
SECTION A — FORMULA SHEET
Basic Definitions
- Vector: Quantity with magnitude and direction
- Position vector of point P(x,y,z): r = xî + yĵ + zk̂
- Magnitude: |r| = √(x²+y²+z²)
- Unit vector: r̂ = r/|r|
Vector Operations
- Addition: (a₁î+a₂ĵ+a₃k̂) + (b₁î+b₂ĵ+b₃k̂) = (a₁+b₁)î + (a₂+b₂)ĵ + (a₃+b₃)k̂
- Scalar multiplication: ka = ka₁î + ka₂ĵ + ka₃k̂
- Section formula (internal): r = (mb + na)/(m+n)
Dot Product (Scalar Product)
- a·b = |a||b|cosθ
- a·b = a₁b₁ + a₂b₂ + a₃b₃
- a·a = |a|²
- a ⊥ b ⟺ a·b = 0
- cosθ = a·b / (|a||b|)
- Projection of a on b = a·b/|b| = (a·b̂)
Cross Product (Vector Product)
- |a × b| = |a||b|sinθ
- a × b = |î ĵ k̂ / a₁ a₂ a₃ / b₁ b₂ b₃| (determinant form)
- a ∥ b ⟺ a × b = 0
- î × ĵ = k̂, ĵ × k̂ = î, k̂ × î = ĵ
- î × î = ĵ × ĵ = k̂ × k̂ = 0
- Area of parallelogram = |a × b|
- Area of triangle = ½|a × b|
Scalar Triple Product
- [a b c] = a·(b × c) = |a₁ a₂ a₃ / b₁ b₂ b₃ / c₁ c₂ c₃|
- Coplanar vectors: [a b c] = 0
- Volume of parallelepiped = |[a b c]|
SECTION B — METHODS
Finding Unit Vector:
- Write vector a = a₁î + a₂ĵ + a₃k̂
- Find |a| = √(a₁²+a₂²+a₃²)
- Unit vector â = a/|a|
Finding Angle Between Vectors:
- Find a·b = a₁b₁+a₂b₂+a₃b₃
- Find |a| and |b|
- cosθ = a·b/(|a||b|)
- θ = cos⁻¹(result)
Cross Product (Determinant Method):
- Write 3×3 determinant with î, ĵ, k̂ in row 1
- Components of a in row 2; b in row 3
- Expand along row 1 with cofactor signs (+−+)
SECTION C — SHORTCUTS
- Perpendicular check: dot product = 0
- Parallel check: cross product = 0 (or one is scalar multiple of other)
- Coplanar check: scalar triple product = 0
- Area of ▲ with vertices A, B, C: ½|AB⃗ × AC⃗|
- Projection of a on b: (a·b)/|b| — no need to find angle
SECTION D — COMMON QUESTION TYPES
1 Mark:
- Find unit vector in direction of given vector
- Find |a⃗ + b⃗| or |a⃗ − b⃗|
2 Mark:
- Find angle between two vectors
- Find projection of a on b
3–4 Mark (Most repeated 2014–2025):
- Find area of triangle/parallelogram using cross product
- Prove vectors are coplanar using scalar triple product
- Find vector perpendicular to two given vectors
Long Answer:
- Prove result using dot/cross product properties
SECTION E — COMMON MISTAKES
- ❌ Sign error in cross product expansion (cofactor signs)
- ❌ Computing |a × b| instead of |a|·|b|·sinθ and vice versa
- ❌ Forgetting ½ for triangle area (cross product gives parallelogram area)
- ❌ Not verifying if question asks for vector or scalar answer
SECTION F — SCORING STRATEGY
- Cross product: Write determinant fully — step marks available
- Scalar triple product: Write determinant and evaluate
- State clearly: "Since a·b = 0, vectors are perpendicular"
CHAPTER 11: THREE DIMENSIONAL GEOMETRY (3D)
SECTION A — FORMULA SHEET
Direction Cosines & Ratios
- l, m, n = direction cosines: l = cosα, m = cosβ, n = cosγ
- l² + m² + n² = 1
- If DRs are a, b, c → DCs = a/√(a²+b²+c²), etc.
Equation of a Line
- Cartesian: (x−x₁)/a = (y−y₁)/b = (z−z₁)/c
- Vector form: r = a + λb
- Through two points: (x−x₁)/(x₂−x₁) = (y−y₁)/(y₂−y₁) = (z−z₁)/(z₂−z₁)
Angle Between Two Lines
- cosθ = |l₁l₂ + m₁m₂ + n₁n₂|
- cosθ = |b₁·b₂| / (|b₁||b₂|)
- Lines are perpendicular if b₁·b₂ = 0
- Lines are parallel if b₁ = λb₂
Equation of a Plane
- General: ax + by + cz = d
- Normal form: r·n⃗ = d
- Through point (x₁,y₁,z₁): a(x−x₁)+b(y−y₁)+c(z−z₁) = 0
- Intercept form: x/a + y/b + z/c = 1
- Through 3 points: Use determinant form
Distance Formulas
- Distance from point P(x₁,y₁,z₁) to plane ax+by+cz+d=0: d = |ax₁+by₁+cz₁+d| / √(a²+b²+c²)
- Distance between parallel planes ax+by+cz=d₁ and ax+by+cz=d₂: d = |d₁−d₂| / √(a²+b²+c²)
Angle Between Line and Plane
- sinθ = |b·n⃗| / (|b||n⃗|)
Angle Between Two Planes
- cosθ = |n₁·n₂| / (|n₁||n₂|)
Shortest Distance Between Skew Lines
- SD = |(a₂−a₁)·(b₁×b₂)| / |b₁×b₂|
- For parallel lines: SD = |(a₂−a₁)×b| / |b|
SECTION B — METHODS
Finding Equation of Plane Through 3 Points:
- Find two vectors from first point to other two (AB⃗, AC⃗)
- Find normal n = AB⃗ × AC⃗
- Plane equation: n·(r−a) = 0
Angle Between Two Planes:
- Identify normal vectors n₁ and n₂
- cosθ = |n₁·n₂| / (|n₁||n₂|)
- θ = cos⁻¹(result)
Foot of Perpendicular from Point to Plane:
- Line through point P with direction = normal of plane
- Find intersection of this line with plane
- That intersection = foot of perpendicular
SECTION C — SHORTCUTS
- Parallel planes: Same normal vector (coefficients proportional)
- Perpendicular planes: n₁·n₂ = 0
- Line || plane: b·n = 0
- Line ⊥ plane: b ∥ n
- Shortest distance (skew lines): Memorize SD formula exactly
SECTION D — COMMON QUESTION TYPES
1 Mark:
- Find direction cosines from direction ratios
- Check if lines are perpendicular/parallel
2 Mark:
- Find angle between line and plane
- Write equation of plane in intercept form
3–4 Mark (Most repeated 2014–2025):
- Find shortest distance between skew lines
- Find equation of plane through 3 points
- Find distance from point to plane
Long Answer:
- Image/foot of perpendicular from point to plane
- Equation of plane containing two given lines
SECTION E — COMMON MISTAKES
- ❌ Confusing DCs with DRs (must normalize DRs)
- ❌ Using wrong formula for angle (line-plane vs plane-plane)
- ❌ Forgetting absolute value in distance/angle formulas
- ❌ Error in cross product for normal vector calculation
SECTION F — SCORING STRATEGY
- Direction cosines: Write formula, substitute — 2 quick marks
- Plane through 3 points: Show cross product and final equation
- Distance from point to plane: Pure formula substitution — guaranteed marks
CHAPTER 12: LINEAR PROGRAMMING
SECTION A — FORMULA SHEET
Key Definitions
- Objective Function: Z = ax + by (to maximize or minimize)
- Constraints: Linear inequalities in x, y
- Feasible Region: Set of all points satisfying all constraints
- Corner Points: Vertices of feasible region
- Optimal Solution: Corner point where Z is maximum/minimum
- Bounded Region: Enclosed feasible region
- Unbounded Region: Open feasible region extending to infinity
Fundamental Theorem
- If optimal solution exists, it occurs at a corner point
- For bounded region: Both max and min exist
- For unbounded region: May not have both max and min
SECTION B — METHODS
Solving LPP:
- Identify objective function Z = ax + by
- Write all constraints as inequalities
- Draw lines for each constraint (find x and y intercepts)
- Shade feasible region (intersection of all half-planes)
- Identify corner points (vertices) — solve pairs of equations
- Evaluate Z at each corner point
- Identify maximum or minimum
- State: "Z is maximum/minimum at (x,y) = value"
Corner Point Calculation:
- Solve two boundary lines simultaneously at each vertex
- Use substitution or elimination method
SECTION C — SHORTCUTS
- Non-negativity constraints: x ≥ 0, y ≥ 0 → only first quadrant
- Check ALL corner points — never assume minimum is at origin
- Unbounded region: Draw line ax+by = max value; if no point of feasible region in open half-plane → max is valid
- Graph neatly: Label all corner points, region must be shaded
- Calculate Z at each vertex — use a table
SECTION D — COMMON QUESTION TYPES
4–5 Mark (ONLY TYPE — this chapter is always one long question):
- Maximize/minimize Z = ax+by subject to constraints
- Real-world LPP: manufacturing, profit maximization, diet problem
Case Study (2 marks each):
- Identify feasible region from graph
- Find corner point coordinates
- Find maximum/minimum Z
SECTION E — COMMON MISTAKES
- ❌ Not shading feasible region correctly (wrong side of inequality)
- ❌ Missing a constraint in the system
- ❌ Not checking all corner points
- ❌ Not stating final answer with Z value AND point
- ❌ Ignoring non-negativity constraints
SECTION F — SCORING STRATEGY
- Draw graph: Compulsory — marks for graph, region, and labels
- Table of Z values: Write clearly at each corner point
- State result: "Maximum Z = ... at (x,y) = ..." — this line is a mark
- This chapter is highly scoring — complete solution guaranteed if steps followed
CHAPTER 13: PROBABILITY
SECTION A — FORMULA SHEET
Basic Probability
- P(A) = n(A)/n(S), 0 ≤ P(A) ≤ 1
- P(A') = 1 − P(A)
- P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
- P(A ∩ B) = 0 if A, B mutually exclusive
Conditional Probability
- P(A|B) = P(A ∩ B) / P(B), P(B) ≠ 0
- P(A ∩ B) = P(B) · P(A|B) = P(A) · P(B|A)
Independence
- A, B are independent if P(A ∩ B) = P(A)·P(B)
- Equivalently: P(A|B) = P(A) or P(B|A) = P(B)
Total Probability Theorem
- If B₁, B₂, ..., Bₙ form a partition of sample space:
- P(A) = Σ P(Bᵢ) · P(A|Bᵢ)
Bayes' Theorem
- P(Bᵢ|A) = [P(Bᵢ)·P(A|Bᵢ)] / [Σ P(Bⱼ)·P(A|Bⱼ)]
- Numerator = one branch; Denominator = sum of all branches
Binomial Distribution
- X ~ B(n, p): P(X = r) = ⁿCᵣ · pʳ · (1−p)^(n−r)
- Mean = np
- Variance = npq = np(1−p)
- Standard Deviation = √(npq)
- q = 1 − p
Random Variables
- E(X) = Σ xᵢ·P(xᵢ) (Expected Value / Mean)
- Var(X) = E(X²) − [E(X)]² = Σxᵢ²·P(xᵢ) − [E(X)]²
SECTION B — METHODS
Bayes' Theorem (Tree Diagram Method):
- Identify prior probabilities P(Bᵢ) for each hypothesis
- Write conditional probabilities P(A|Bᵢ)
- Compute each branch product: P(Bᵢ)·P(A|Bᵢ)
- Total P(A) = sum of all branch products
- P(Bᵢ|A) = branch product / P(A)
Probability Distribution Table:
- List all possible values of X
- Find P(X = x) for each value
- Verify Σ P(xᵢ) = 1
- Find E(X) = Σ xᵢ·P(xᵢ)
- Find Var(X) = Σxᵢ²·P(xᵢ) − [E(X)]²
Binomial Distribution:
- Check: fixed n, only 2 outcomes, independent trials, constant p
- Write X ~ B(n,p)
- Use P(X=r) = ⁿCᵣ·pʳ·qⁿ⁻ʳ
- Mean = np, Variance = npq
SECTION C — SHORTCUTS
- Bayes' tree: Draw tree diagram, label all branches — saves confusion
- P(A ∩ B) = P(A)·P(B) only for independent events
- Partition check: All Bᵢ mutually exclusive + exhaustive
- Binomial check: n, p, q = 1−p → three values determine everything
- Verify distribution: Σ P(X) must = 1 exactly
SECTION D — COMMON QUESTION TYPES
1 Mark:
- Find P(A|B) from given values
- Identify independent/dependent events
2 Mark:
- Find P(A ∪ B) using addition formula
- Check independence of events
3–4 Mark (Most repeated 2014–2025):
- Bayes' theorem word problem (factory, disease, bag-of-balls type)
- Probability distribution table + mean/variance
- Binomial distribution: find P(X=k), mean, variance
Long Answer:
- Full Bayes' theorem with 3 hypotheses
- Probability distribution of X from game/dice/card experiments
SECTION E — COMMON MISTAKES
- ❌ Using P(A)·P(B) formula for non-independent events
- ❌ Not verifying Σ P(xᵢ) = 1 in distribution table
- ❌ Confusing P(A|B) with P(B|A)
- ❌ Bayes': using wrong denominator (not summing all branches)
- ❌ Variance: computing Σxᵢ²·P(xᵢ) but forgetting to subtract [E(X)]²
SECTION F — SCORING STRATEGY
- Bayes' theorem: Show table or tree, each correct row = partial mark
- Distribution table: Layout clearly — examiners mark table row by row
- State: P(X=r) = ⁿCᵣ·pʳ·qⁿ⁻ʳ before substituting values
- Probability is the highest weightage topic — do not skip
End of Part 3 — Chapters 10 to 13 Continue in: MATHS_MASTER_PART4_STRATEGIES.md
📘 CBSE CLASS 12 — MASTER MATHEMATICS SYSTEM
PART 4: FINAL MASTER SECTION — STRATEGIES, REVISION & SCORING
Chief Examiner Edition | 2014–2025 Trend Analysis
1. ULTRA RAPID 1-DAY REVISION FORMULA LIST
RELATIONS & FUNCTIONS
- Equivalence = Reflexive + Symmetric + Transitive
- Bijective = One-One + Onto → Inverse exists
- (g∘f)(x) = g(f(x)); (AB)⁻¹ = B⁻¹A⁻¹
INVERSE TRIG
- sin⁻¹x + cos⁻¹x = π/2; tan⁻¹x + cot⁻¹x = π/2
- cos⁻¹(−x) = π − cos⁻¹x (NOT negative!)
- 2tan⁻¹x = sin⁻¹(2x/1+x²) = tan⁻¹(2x/1−x²)
- tan⁻¹x + tan⁻¹y = tan⁻¹((x+y)/(1−xy)) if xy<1
MATRICES
- Symmetric: Aᵀ = A; Skew: Aᵀ = −A; diagonal of skew = 0
- A = ½(A+Aᵀ) + ½(A−Aᵀ)
- 2×2 inverse: swap diagonal, negate off-diagonal, ÷|A|
DETERMINANTS
- Area of △ = ½|det|
- Collinear ⟺ det = 0
- A⁻¹ = adj(A)/|A|; |adj(A)| = |A|^(n−1)
- AX = B → X = A⁻¹B
CONTINUITY & DIFFERENTIABILITY
- Continuous at a: LHL = RHL = f(a)
- Key: d/dx[sin⁻¹x] = 1/√(1−x²); d/dx[tan⁻¹x] = 1/(1+x²)
- Log diff for (f(x))^g(x) type
- Rolle's: f'(c) = 0; MVT: f'(c) = (f(b)−f(a))/(b−a)
APPLICATIONS OF DERIVATIVES
- Increasing: f'(x) > 0; Decreasing: f'(x) < 0
- Local Max: f'(c)=0, f''(c)<0; Local Min: f'(c)=0, f''(c)>0
- Slope of normal = −1/m (negative reciprocal of tangent)
- f(x+Δx) ≈ f(x) + f'(x)·Δx
INTEGRALS
- ∫eˣ[f(x)+f'(x)]dx = eˣf(x) + C
- ∫1/(x²+a²) = (1/a)tan⁻¹(x/a); ∫1/√(a²−x²) = sin⁻¹(x/a)
- IBP (ILATE): ∫uv dx = u∫v dx − ∫(u'∫v dx)dx
- ∫₀ᵃ f(x)dx = ∫₀ᵃ f(a−x)dx (property)
- Even function: ∫₋ₐᵃ = 2∫₀ᵃ; Odd function: = 0
APPLICATIONS OF INTEGRALS
- Area = ∫ₐᵇ [upper − lower] dx
- Area of circle = πr²/4 (first quadrant) × 4 = πr²
DIFFERENTIAL EQUATIONS
- Order = highest derivative; Degree = its power
- IF = e^∫P dx; y·IF = ∫Q·IF dx + C
- Homogeneous: y = vx → dy/dx = v + x·dv/dx
VECTORS
- a·b = |a||b|cosθ; a×b: magnitude = |a||b|sinθ
- Perpendicular: a·b = 0; Parallel: a×b = 0
- Area of △ = ½|a×b|; Parallelogram = |a×b|
- Coplanar: [a b c] = 0
3D GEOMETRY
- l²+m²+n² = 1; DCs = DRs/√(sum of squares)
- Angle between planes: cosθ = |n₁·n₂|/(|n₁||n₂|)
- Distance from point to plane: |ax₁+by₁+cz₁+d|/√(a²+b²+c²)
- Skew line SD: |(a₂−a₁)·(b₁×b₂)|/|b₁×b₂|
LINEAR PROGRAMMING
- Optimal value always at corner point
- Evaluate Z at all vertices; max/min by comparison
PROBABILITY
- P(A|B) = P(A∩B)/P(B)
- Bayes: P(Bᵢ|A) = P(Bᵢ)P(A|Bᵢ)/ΣP(Bⱼ)P(A|Bⱼ)
- Binomial: P(X=r) = ⁿCᵣpʳqⁿ⁻ʳ; Mean=np; Var=npq
- E(X) = Σxᵢ P(xᵢ); Var = Σxᵢ²P(xᵢ) − [E(X)]²
2. SAFE 40 MARK SURVIVAL PLAN
Goal: 40/80 in theory (pass guarantee). Focus on guaranteed-mark sources.
Priority Chapters (Easiest scoring)
| Chapter | Target Marks | Strategy |
|---|---|---|
| Linear Programming | 5 marks | Draw graph + corner points = complete marks |
| Probability | 5–8 marks | Bayes or distribution table = step marks |
| Determinants (Area/Matrix method) | 4 marks | Pure formula substitution |
| Vectors | 4 marks | Cross/dot product — formula-based |
| ITF (formulas) | 2–3 marks | Direct identity application |
| Relations (MCQ/1 mark) | 2 marks | Know definition, answer instantly |
| Differential Equations (order/degree) | 1 mark | Free mark |
| Continuity (LHL=RHL check) | 2 marks | Follow 3-step method |
| Integrals (standard formulas) | 4 marks | Memorize 15 standard forms |
Safe Attempt Rule
- Attempt Section A (MCQ) first: 20 questions × 1 mark = 20 marks
- Section B (VSA/SA): Pick 5 easiest from options
- Section C: Attempt LP and Probability fully
- Total strategy: 20 + 10 + 10 = 40 marks minimum
Do NOT skip:
- LP (5-step solution = 5 marks)
- Probability distribution table
- Matrix method for 3 equations
- Area of triangle using determinant
3. 70+ HIGH SCORE STRATEGY
Scoring Breakdown Plan
| Section | Max | Target |
|---|---|---|
| Section A (MCQ + Assertion) | 20 | 18+ |
| Section B (2-mark SA) | 20 | 16+ |
| Section C (3-mark SA) | 18 | 15+ |
| Section D (5-mark LA) | 20 | 16+ |
| Section E (Case Study) | 12 | 10+ |
Total Target: 75+/80
High-Yield Topics for 70+
- Integrals (Ch 7): 12–15 marks in paper — highest weightage
- Probability (Ch 13): 8 marks — Bayes always comes
- Calculus chain (Ch 5, 6): 8–10 marks
- 3D & Vectors (Ch 10, 11): 10 marks — formula-based, reliable
- Determinants (Ch 4): 5 marks — straightforward proofs
70+ Habits
- ✅ Write ALL derivation steps explicitly
- ✅ State theorems before applying them
- ✅ Draw figures for Area, 3D, LP questions
- ✅ Show substitution, don't skip steps
- ✅ Write "Hence Proved" / "Hence Z is max at..." at end
- ✅ Double-check sign in cross product, cofactors
- ✅ Verify: Σ P(xᵢ) = 1 in distribution
Chapters to Master Completely (All marks available)
- Linear Programming: Fixed format → 100% marks possible
- Probability: Learn 3 templates → full marks
- Applications of Integrals: 3 question types → all solvable
- Vector Identities: 15 formulas → all questions covered
4. EXAM HALL TIME MANAGEMENT PLAN
Total Time: 180 minutes for 80 marks theory paper
Recommended Time Split
| Phase | Time | Activity |
|---|---|---|
| Reading Time | 15 min | Read ALL questions, mark easy/medium/hard |
| Section A (MCQ) | 25 min | 20 questions, 1.25 min each — no calculation shown |
| Section B (2-mark) | 20 min | 5 questions × 4 min |
| Section C (3-mark) | 25 min | 6 questions × ~4 min |
| Section D (5-mark) | 40 min | 4 questions × 10 min |
| Section E (Case Study) | 25 min | 3 case studies × ~8 min |
| Review + Final check | 10 min | Verify +C, units, conclusions |
Priority Order of Attempt
- Section A — Always first (no steps, quick marks)
- Linear Programming — Guaranteed 5 marks, do early
- Probability Distribution / Bayes — Do while fresh
- Any Integration question you know fully — Do completely
- Difficult proofs — Attempt last
Time Warning Signs
- Spending >10 min on single non-LA question → Move on, attempt later
- Not attempting LP → Emergency: attempt LP in last 10 min minimum
- Running out of time → Write formulas and setup even if can't solve = partial marks
Golden Rules in Exam Hall
- Never leave Section A blank — guess if unsure (no negative marking)
- Always attempt every LA even partially — partial marking always available
- Write neatly: messy answer = examiner cannot award step marks
- Box/underline final answers: Makes marks easier to award
- Don't erase crossed work: Crossed work can still get partial credit
5. MARKING SCHEME UNDERSTANDING GUIDE
How CBSE Examiners Award Marks
For Proof-Type Questions (Determinant, Vector, Log Diff)
| Step | Marks |
|---|---|
| Correct setup / writing formula | ½ to 1 mark |
| Correct intermediate working | 1 mark per stage |
| Correct final answer | 1 mark |
| Conclusion statement | ½ mark |
Rule: Skipping steps = losing step marks. Write every line.
For Word Problems (AOD, Probability, DE)
| Step | Marks |
|---|---|
| Correct variable definition | ½ mark |
| Correct equation setup | 1 mark |
| Correct differentiation/calculation | 1 mark |
| Setting derivative = 0 + solving | 1 mark |
| Verification (2nd derivative or sign) | ½ mark |
| Final answer with units/conclusion | ½ mark |
For Bayes' Theorem
| Step | Marks |
|---|---|
| Identifying prior probabilities | 1 mark |
| All conditional probabilities correct | 1 mark |
| Total probability (denominator) | 1 mark |
| Final Bayes fraction + simplification | 1 mark |
For Integration (Definite/Indefinite)
| Step | Marks |
|---|---|
| Correct identification of method | ½ mark |
| Correct step (substitution, IBP) | 1 mark |
| Integration correct | 1 mark |
| Limits applied (for definite) | 1 mark |
| Final answer simplified | ½ mark |
| +C for indefinite | ½ mark |
Partial Marking Philosophy
- Always attempt: Even 1 correct step = 1 mark
- Formula written but wrong calculation: Typically 1 mark safe
- Method correct but arithmetic error: Usually −1 mark only
- Blank answer: 0 marks — never better than a partial attempt
Common Examiner Expectations
- For "Prove that": Must show clear LHS → RHS progression with steps
- For "Find": Show all working, then state answer
- For "Verify": State theorem conditions first, then verify each
- For "Solve": Show full solution with +C and particular solution if asked
- Graphs: Must label axes, mark key points, shade correct region (LP)
- Diagrams in 3D: Rough diagram is appreciated, not mandatory
What Gets You FULL Marks
- Correct answer with all steps shown
- Proper mathematical notation (no ambiguity)
- Conclusion line at end of proof
- Units in word problems
- Box or underline final answer
What Gets You ZERO Marks
- Blank space
- Only final answer with no working (for LA questions)
- Copied question without any attempt
Most Common Partial Credit Situations
- Integral without +C: −½ mark
- Area answer negative (forgot |·|): Lose ½ to 1 mark
- Matrix inverse formula wrong: Lose 1 mark but gain rest
- Wrong limits in definite integral: Lose 1 mark on evaluation step
📋 MASTER FILE INDEX
| File | Chapters |
|---|---|
| MATHS_MASTER_PART1_CH1-5.md | Ch 1: Relations & Functions, Ch 2: ITF, Ch 3: Matrices, Ch 4: Determinants, Ch 5: Continuity & Differentiability |
| MATHS_MASTER_PART2_CH6-9.md | Ch 6: AOD, Ch 7: Integrals, Ch 8: Applications of Integrals, Ch 9: Differential Equations |
| MATHS_MASTER_PART3_CH10-13.md | Ch 10: Vectors, Ch 11: 3D Geometry, Ch 12: LP, Ch 13: Probability |
| MATHS_MASTER_PART4_STRATEGIES.md | Rapid Revision, 40-Mark Plan, 70+ Strategy, Time Management, Marking Scheme |
"Marks are not lost in the exam hall — they are lost in preparation. Use this system, follow the structure, and every mark is within reach." — CBSE Chief Examiner Mindset
End of Master Mathematics System — All 13 Chapters Complete